[concurrency-interest] Ordering Question

Justin Sampson jsampson at guidewire.com
Wed Jul 20 01:19:58 EDT 2016

Hi Michael,

I'm confused by the question. If T2 runs completely after T1, you get A=1 and B=0 without any reordering whatsoever. The only outcome that is impossible without reordering is A=0 and B=0. Is that the case you're asking about?


From: Concurrency-interest [mailto:concurrency-interest-bounces at cs.oswego.edu] On Behalf Of Michael Barker
Sent: Tuesday, July 19, 2016 7:11 PM
To: concurrency-interest
Subject: [concurrency-interest] Ordering Question


I have a question around ordering of events.

Given, threads (T1, T2), and variables (A, B, X, Y) where X and Y are shared on the heap and visible to T1 and T2.


X = 0
Y = 0;

1) X = 1 (lazySet/putOrdered)
2) B = Y (volatile read)

3) Y = 1 (compare and set)
4) A = X (volatile read)

Is it possible to get a final state of A = 1 and B = 0?

My current suspicion is that it is, due to 1) and 2) being reordered.  If so, can the final state of A=1, B=0 be prevented by strengthening 1) to be a volatile store?

Michael Barker.
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