[concurrency-interest] What can an incorrectly synchronized read see?

Bobrowski, Maciej Maciej.Bobrowski at morganstanley.com
Wed Sep 28 06:47:37 EDT 2016

´╗┐Right, so the only invalid execution in any possible sequencing is the (1, 0) which was the main question of this post, correct?

-----Original Message-----
From: Concurrency-interest [mailto:concurrency-interest-bounces at cs.oswego.edu] On Behalf Of Aleksey Shipilev
Sent: 28 September 2016 10:01
To: dholmes at ieee.org; concurrency-interest at cs.oswego.edu
Subject: Re: [concurrency-interest] What can an incorrectly synchronized read see?

On 09/28/2016 10:52 AM, David Holmes wrote:
> Is there a typo there Aleksey, the only OK outcome you listed was (0,0). ???

Note that in my note, there are two classes of executions, depending on the sequence of locks/unlocks in (R)eader and (W)riter.

(unsync, sync):
 (0, 0): justified by executions with R->W sequencing  (0, 1): justified by executions with W->R sequencing  (1, 0): is not justified by any executions  (1, 1); justified by executions with W->R sequencing

>> -----Original Message-----
>> From: Concurrency-interest [mailto:concurrency-interest- 
>> bounces at cs.oswego.edu] On Behalf Of Aleksey Shipilev Note that 
>> unsynchronized read can read either "0" or "1", regardless of if 
>> synchronized sees "1" after it.

This is for W->R sequencing.

>> Now, let's see what (V1, V2) combinations do not violate JMM:
>>  (0, 0) -- ok, both see some (default?) "0" write from before  (1, 0) 
>> -- NOT OK, r(val):V1 cannot see the w(val,1) that's after in HB!
>>  (0, 1) and
>>  (1, 1) -- NOT OK for this particular execution, because r(val):V2 
>> sees the "future" write w(val,1). Notice, however, that both these 
>> results are justified by the execution at the very beginning, when 
>> Writer and Reader are sequenced in another order.

This is for R->W sequencing.



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