[concurrency-interest] Future.isCompletedNormally Future.isCompletedAbnormally
thurston at nomagicsoftware.com
Thu Mar 5 01:58:56 EST 2015
What would be the memory consistency effects of
isCompletedNormally() ==> true be?
I assume the "asynchronous computation" would happen-before in that case.
Also, just for discussion, what if you have some :
DefaultFuture<T>(default:T, () -> T) implements Future<T>
what would the semantics of isCompletedAbnormally() be in such a case?
Might burden the implementation unnecessarily in such a case to strictly
I'm not sure how FJP uses FJT's methods, but it doesn't necessarily follow
that those methods should be promoted to the base interface.
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